Question

the product of two conjucativ integers is 600.find second integers​

Answer 1

Answer:-

Let x be the first integer and x+1 be the second integer

Product of these two integers =x(x+1)=600

⇒x²+x−600=0

⇒(x−24)(x+25)=0

⇒x=24 or x=−25

∴ The first integer is 24.

So, the second integer will be x+1=25.

Answer 2

Answer:

24 and 25

Step-by-step explanation:

Let the smaller integer be x

Therefore the other integer is x+1

So

x(x+1)=600

x^2+x-600=0

x^2+25x-24x-600=0

x(x+25)-24(x+25)=0

(x-24)(x+25)=0

So , since x cannot be negative

x-24=0

x=24

So the integers are 24 and 25

Hope this helps