Question

The product of two consecutive even numbers is 7568. What is 150% of the sum of the two numbers?​

Answer 1

Answer:

As the square root 7568 lies between 2 even numbers 86

and 88,

7568=86×88

Thus the two consecutive even numbers whose product is 7568 are 86 and 88

.Required number = 150/100 (86+88)=261.

Step-by-step explanation:

I hope that it will help you

Answer 2

Answer:

As the square root 7568 lies between 2 even numbers 86 and 88,

7568=86×88

Thus the two consecutive even numbers whose product is 7568 are 86 and 88

.Required number =

100

150

(86+88)=261.