Question

The product of two consecutive even positive integers is 1088 find the sum of the two integers

Answer 1

Answer:

66

Step-by-step explanation:

Let the consecutive even positive numbers be n and n+2

Given

n(n+2) = 1088

=> n² + 2n - 1088 = 0

= n² + 34n - 32n - 1088 = 0

=> n(n+34) - 32(n+34) = 0

=> (n+34)(n-32) = 0

=> n = -34 or 32

=> n = 32 (Since number needs to be positive).

Thus the 2nd even number is 32+2 = 34.

Sum of the numbers = 34+32 = 66.