The product of two consecutive integer is 306. Find the quadratic representation of this situation
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Let the first integer be x
Then, the consecutive integer=x+1
Quadratic equation thus formed
=x(x+1)=306
=x^2+x-306=0
Then, the consecutive integer=x+1
Quadratic equation thus formed
=x(x+1)=306
=x^2+x-306=0
shubhamtiwari31:
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Let the first integer be a
Second integer = a+1
According to question
=> a(a+1) = 306
=> a^2 +a = 306
=> a^2 +a - 306 =0
This is the required quadratic equation....
Second integer = a+1
According to question
=> a(a+1) = 306
=> a^2 +a = 306
=> a^2 +a - 306 =0
This is the required quadratic equation....
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