Question

The product of two consecutive multiples
Of 6 is 432 which are the numbers?​

Answer 1

Step-by-step explanation:

let the two numbers be x and x+6

x(x+6)=432

x^2+6x=432

(x+3)^2=432+9

x+3^2=441

x+3=+or - 21

x=21-3=18

x=-21-13=24

the value of x are 18 and 24

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Answer 2

Given :-

Let the two consecutive number be 6x and 6(x+1)

Here,

The product of two consecutive number is 432.

Solution :-

Product of two consecutive number

6x ( 6x + 6) = 432

36x^2 + 36x = 432

36x^2 + 36x - 432 = 0

9x^2 + 9x - 108 = 0

Now, By Using quadratic formula ,

-b ± √b^2 -4ac / 2a

Here, a = 9 , b = 9 , c = -108

Put the required values in the formula,

-9 ± √81 - 4* 9 * -108 / 2 * 9

-9 ± √81 + 3888 /18

-9 ± √3969/ 18

-9 ± 63/18

3 , -4

We neglect -4 because roots may not be negative.

Therefore,

x = 3

So,

6x = 6* 3 = 18

6x + 6 = 18 + 6 = 24