Question

The product of two consecutive natural number is 132. find the numbers​

Answer 1

n2 + n – 132 = 0 Since the answer is a positive integer, throw out -12 answer. The two consecutive positive integers whose product is 132 are 11 and 12.

Answer 2

The natural numbers are 11 and 12.

• An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C.
• Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Here, according to the given information, we are given that,

The product of two consecutive natural number is 132.

Let the two number be x and (x+1).

Then, we have,

$x.(x+1)=132.$

Or, $x^{2} +x-132=0.$

Or, $x^{2} +12x-11x-132=0.$

Or, $x(x+12)-11(x+12)=0.$

Or, $(x-11)(x+12)=0.$

This means that x is 11, since -12 is not a natural number.

Then, the consecutive natural number = 12.

Hence, the natural numbers are 11 and 12.

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