Question

The product of two consecutive natural numbers which are multiples of 3 is equal to 810.Find the two numbers

Answer 1

Answer:

Let the first number be 3x

second be 3(x+1)=3x+3

3x+3x+3=810

6x+3=810

6x=810–3

6x=807

x=807÷6

x=134.5

First number = 3x = 3× 134.5 = 403.5

Second number = 3x+3 = 3× 134.5 + 3 = 403.5 + 3 = 406.5