Question

the product of two consecutive positive integers is 110.what are the integers?

Answer 1

hey sakna here. first number = x. since this no are consecutive so. second number = x+1. now according to question

Answer 2

The positive integers that have a product of 110 are 10 and 11.

• This issue can be resolved using algebra. If x is the initial positive integer, then x+1 would be the next positive integer after that. The answer to the issue is 110, which is the product of these two numbers. As a result, we may write an equation as:

• x(x+1) = 110

• When we increase the left side of the equation, we obtain:

• x^2 + x = 110

• The equation may now be rearranged into a common quadratic form:

• x^2 + x - 110 = 0

• Using the quadratic formula, we can find x:

• x = (-b (b2 - 4ac))/(2a)

• where a=1, b=1, and c=–110.

• By entering these values, we obtain:

• x = (-1 ± √(1^2 - 4(1)(-110))) / 2(1) (1)

• If we simplify, we get:

• x = (-1 ± √441) / 2

• This may be further condensed to get:

• x = (-1 ± 21) / 2

• The following are potential values for x:

• x = (-1 + 21) / 2 = 10 or x = (-1 - 21) / 2 = -11

• Yet, the answer is x = 10 because we are seeking for positive integers. Hence, 10 and 11 are the next two positive integers in line.

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