the product of two consecutive positive multiple of 3 is 180 find the numbers
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let one of the multiple of 3 be 3x,3x+3
3x(3x+3)=180
9x2+ 9x=180
9x2+9x-180=0
X2+x-20=0
(x-4)+(x+5)
x=4,x=5
multtiples of 3 are 12,15 and -15-12
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