Question

The Product of two consecutive positive multiples of 3 is 180.Find the numbers.

Answer 1

Let the numbers be 3x & 3x+3
  3x(3x+3)=270
/3
x(3x+3)=90
3x^2+3x=90
/3
 x^2+x-30=0
x^2+6x-5x-30=0
(x+6)(x-5)=0
 x=-6
 x=5
plug the value of x in 3x & 3x+3
the numbers are 15 & 18
OR -15,-18

Answer 2

Answer:

Step-by-step explanation:

Let the numbers be 3x & 3x+3

 3x(3x+3)=270  

/3  

x(3x+3)=90  

3x^2+3x=90  

/3

x^2+x-30=0  

x^2+6x-5x-30=0  

(x+6)(x-5)=0

x=-6

x=5  

plug the value of x in 3x & 3x+3  

the numbers are 15 & 18  

OR -15,-18

hope it would be helpful..............................................