Question

the Product of two even numbers is 2020 find the sum of those two numbers. find all possibilities​

Answer 1

Answer:

212 and 1012

Step-by-step explanation:

let the even no be 2x and 2y

2x*2y=2020

x*y=505

505=5*101 and 505=1*505

Therefore the no are

(10 and 202) or (1010 and 2)

(10*202=2020 and 1010*2=2020)

Sums are 212 and 1012

Answer 2

SOLUTION

GIVEN

Product of two even numbers is 2020 find the sum of those two numbers.

TO DETERMINE

All possibilities

EVALUATION

Let two even numbers are 2M and 2N

By the given condition

2M × 2N = 2020

⇒ 4MN = 2020

⇒ MN = 505

505 = 5 × 101

So there are only two possibilities

M = 5 , N = 101

M = 101 , N = 5

M = 1 , N = 505

M = 505 , N = 1

Consequently the numbers are

10 , 202

2 , 1010

Hence the required sum

= 10 + 202

= 212

OR

Hence the required sum

= 2 + 1010

= 1012

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