Question

The product of two natural numbers, one of which is greater than the other by 6, is 187

Answer 1

Let the first number be a

Second number = (a+6)

According to question,

a ( a + 6) = 187

=> a^2 + 6a - 187 = 0

=> a^2 + 17a - 11a - 187 = 0

=> a ( a +17) - 11(a + 17) =0

=> (a+ 17) (a - 11) =0

a = - 17 and 11

Neglecting negative value, we get

a = 11

First number = 11

Second number = 17