The product of two negative integers is 112. If one of the integer is 9 more than other than the greater integer is_______ -16,16,7,-7
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Hey
here's your answer !!
Let the smaller number be x
There fore ,
The greater number will be ( x + 9 )
Acc. to the question ,
x ( x + 9 ) = 112 ,
=> x² + 9x - 112 = 0 ,
=> x² + 16x - 7x - 112 = 0 ,
=> x ( x + 16 ) - 7 ( x + 16 ) = 0 ,
=> ( x - 7 ) ( x + 16 ) = 0 .
So ,
either ( x - 7 ) = 0 or ( x + 16 ) = 0 .
so if ( x - 7 ) = 0 ,
then ( x + 16) = 0
=> x = -16 .
and if ( x + 16 ) = 0 ,
then ( x - 7 ) = 0
=> x = 7 .
But acc. to the question ,
x is a negative integer .
so, actual value of x is -16 .
so the two numbers are ----->
( a ) -16 .
( b ) -16 + 9 = -7 .
Hope it helps !!
here's your answer !!
Let the smaller number be x
There fore ,
The greater number will be ( x + 9 )
Acc. to the question ,
x ( x + 9 ) = 112 ,
=> x² + 9x - 112 = 0 ,
=> x² + 16x - 7x - 112 = 0 ,
=> x ( x + 16 ) - 7 ( x + 16 ) = 0 ,
=> ( x - 7 ) ( x + 16 ) = 0 .
So ,
either ( x - 7 ) = 0 or ( x + 16 ) = 0 .
so if ( x - 7 ) = 0 ,
then ( x + 16) = 0
=> x = -16 .
and if ( x + 16 ) = 0 ,
then ( x - 7 ) = 0
=> x = 7 .
But acc. to the question ,
x is a negative integer .
so, actual value of x is -16 .
so the two numbers are ----->
( a ) -16 .
( b ) -16 + 9 = -7 .
Hope it helps !!
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