the product of two number is 972 and their quietient is 4÷3 find the numbers
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according to the question=
let the two numbers be a and b
a×b =972... equation (1)
a/b=4/3
3a=4b
b=3a/4
now put this value of b in equation (1)
a×3a/4=972
3a²= 972×4
a²=3888/3
a²=1296
a=√1296
a=36
let the two numbers be a and b
a×b =972... equation (1)
a/b=4/3
3a=4b
b=3a/4
now put this value of b in equation (1)
a×3a/4=972
3a²= 972×4
a²=3888/3
a²=1296
a=√1296
a=36
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