The product of two numbers is 120 and the sum of their squares is 289. The sum of the number is:
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consider the two number be x and y
xy=120
x^2+y^2=289
then x+y=is the question
formula (x+y)^2=x^2+y^2+2xy
=289+2(120)
=289+240
=529
(x+y)^2=529, taking square root on both side
then x+y=23
the sum of the number is 23
xy=120
x^2+y^2=289
then x+y=is the question
formula (x+y)^2=x^2+y^2+2xy
=289+2(120)
=289+240
=529
(x+y)^2=529, taking square root on both side
then x+y=23
the sum of the number is 23
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