Question

The product of two numbers is 120 and the sum of their squares is 289.the defarance of the square of two number is
Options
161
163
169

Answer 1

Answer:

161

Step-by-step explanation:

Let the numbers be x and y.

Then, xy = 120 and

x2 + y2 = 289.

On further solving -

 (x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529

 x + y = √529= 23.

Thus the numbers will be x = 15 and b = 8

Thus x² = 15² = 225

and y² = 8 = 64

Difference = 225-64 = 161

Answer 2

Answer:

161

Step-by-step explanation:

x*y=120 & x^2+y^2=289

find x^2-y^2

solution

x^2-y^2

= (x-y)(x+Y)

=((x-y)^2*(x+y)^2)^1/2

=((x^2+y^2+2xy)*(x^2+y^2-2xy))^1/2

=((289+240)*(289-240))^1/2

=23*7

=161