Math, asked by ali2397, 7 hours ago

The product of two numbers is 128. If the first number is twice the second number ,what is the first number?​

Answers

Answered by AllenGPhilip
4

Answer:

First no: = 2y = 8×2 = 16

Second no: = y = 8

Step-by-step explanation:

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Question:-

The product of two numbers is 128. If the first number is twice the second number

Required:-

what is the first number

Solution-

Let the no: be 'x' & 'y'

Given xy = 128

First no: be 'x'

Second no: be 'y'

If the first number is twice the second number

First no: be 2y

Second no: be y

2y × y = 128

2y² = 128

y² = 64

y = 8

First no: = 2y = 8×2 = 16

Second no: = y = 8

Answered by prachibarapatre
0
  • It is given that the product of 2 numbers is 128.

       also, the first number is twice the other.

  • So if we assume the second number to be 'x' ,

       then the first number will be '2x'

Now, as per the question

x ( 2x) = 128

2x² = 128

x²= 64

x= 8

Now, as the first number is 2x, then putting the value of x

So, the first number will be 16

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