the product of two numbers is 1728. if their hcf is 12 find their lcm step by step simple
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Step-by-step explanation:
IsWhen product of numbers A and B, and the HCF are given, we find the LCM by using the identity H x L = A x B.
So, L = 1728 /12 = 144
LCM is always divisible by HCF.
L/H = 144/12 = 12
Now 12 can be split only as 1x 12 or 2x6 or 3 x 4
We take each pair and multiply the numbers in each pair by the HCF.
We get now the pairs (12, 144), (24, 72) and (36, 48)
We can observe that each pair except (2, 72) satisfies the criteria: Product of numbers = 1728, HCF = 12 and LCM = 144 (which we obtained)
Hence there are two pairs satisfying the given criteria.
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