Question

The product of two numbers is
3888.
If one number is 12 times the other.
What will be the numbers ?​

Answer 1

The numbers are 216 and 18

Given :

• The product of two numbers is 3888.

• One number is 12 times the other.

To find :

The numbers

Solution :

Step 1 of 2 :

Form the equation to find the numbers

Here it is given that one number is 12 times the other

Let the numbers are n and 12n

Since product of two numbers is 3888

By the given condition

$\displaystyle \sf n \times 12n = 3888$

Step 2 of 2 :

Find the numbers

$\displaystyle \sf n \times 12n = 3888$

$\displaystyle \sf{ \implies }12 {n}^{2} = 3888$

$\displaystyle \sf{ \implies }{n}^{2} = \frac{3888}{12}$

$\displaystyle \sf{ \implies }{n}^{2} = 324$

$\displaystyle \sf{ \implies }n = \sqrt{324}$

$\displaystyle \sf{ \implies }n = 18$

First number = 18

Second number = 12 × 18 = 216

Hence two numbers are 216 and 18

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Answer 2

18 and 216 are the two numbers.

Given:

Product of two numbers = 3888

Solution:

Let, the bigger number be 'a' and smaller number be 'b'

According to the question,

$a=12\times b$ -----(1)

Now,

$a\times b = 3888$ -----(2)

Put the value of 'a' from (1) in (2), we get

$12\times b\times b=3888\\12\times b^{2} =3888\\b^{2} =\frac{3888}{12} \\b^{2} =324\\b=\sqrt{324}\\b= 18$

To get the value of 'a' put the value of 'b' in (1)

$a=12\times 18\\a=216$

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