The product of two numbers is 48 and their sum is 19.
what are the numbers????
Answers
Answered by
28
we should algebra to find the numbers logically. not use trial and error or guessing game.
numbers x, y.
x + y = 19 ---- (1)
x y = 48
(x - y)² = (x + y)² - 4 xy = 19² - 4*48 = 361 - 192 = 169
so x - y = 13 ---- (2)
add (1) and (2)... 2x = 32 so x = 16
from (1) , we get y = 3.
So the numbers are 16 and 3.
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another way:
48 = 1 * 2 * 3 * 4 * 6 * 8 * 12 * 16 * 24 * 48
In the factors on the right side, find two factors which will sum to 19. So we can find 3 and 16.
numbers x, y.
x + y = 19 ---- (1)
x y = 48
(x - y)² = (x + y)² - 4 xy = 19² - 4*48 = 361 - 192 = 169
so x - y = 13 ---- (2)
add (1) and (2)... 2x = 32 so x = 16
from (1) , we get y = 3.
So the numbers are 16 and 3.
============================
another way:
48 = 1 * 2 * 3 * 4 * 6 * 8 * 12 * 16 * 24 * 48
In the factors on the right side, find two factors which will sum to 19. So we can find 3 and 16.
kvnmurty:
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Answered by
17
Let the two numbers be x and y.
xy=48
x+y=19
⇒ y=19-x
⇒x(19-x)=48
⇒19x-x²=48
x²-19x+48=0
⇒(x-3)(x-16)=0
Therefore, x=16 (or) x=3.
which implies,
one number is 3,
and the other number is 16.
xy=48
x+y=19
⇒ y=19-x
⇒x(19-x)=48
⇒19x-x²=48
x²-19x+48=0
⇒(x-3)(x-16)=0
Therefore, x=16 (or) x=3.
which implies,
one number is 3,
and the other number is 16.
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