Question

the product of two numbers is 91 and their arthemetic mean is 10 then the two numbers are​

Answer 1

Answer:

let the two number be a & b.so,

a×b=91 -(given)

or, a= 91/b -(1)

Arithematic mean = (a+b)/2

or, 10= (a+b)/2

or,20=a+b

or,20=b/91+b -( by 1)

or,20×91=b+91b

or,1820=92b

therefore, b= 1820/92 =19.78

and a=91/19.78 =4.6

hence the required answer, a=4.6 & b=19.78