Question

The product of two numbers is 96 and their sum is 20. Find the numbers.
please tell​

Answer 1

Answer:

Let the numbers be x, y

Given, x + y = 20 ....(1)

xy = 96....(2)

= > y = 20-x

substitute y = 20 - x in (2)

= > x(20 - x) = 96 = > \( 20x - x^{2} = 96 \)

= > \(x^{2} – 20x +96 = 0 \)

=> x=12 or 8

If x = 12, y= 20 - 12 = 8

If x = 8, y=20-8 = 12

The required 2 numbers are 8 and 12.

Answer 2

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Anyway thanks for answering :)