the product of two rational number is 117 upon 40 if one of them is - 13 upon 5 find the other
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-13/5 × X = 117/40 so, we will divide 117/ 40 by -13/5 to get another one 117/40÷-13/5 = 117/40 × 5/-13 = 9 / -8 and after writing it into standard form it will be -9/8
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Hello friend
Good morning
Given that the product of two rational number is 117/40
One of those rational number is -13/5
Let the another rational number be x.
Therefore -13/5 × x = 117/40
=> x = 117/40 × -5/13
=> x = 9/-8
=> x = -9/8
VERIFICATION :-
RHS = 117/40
LHS = -9/8 × -13/5
= 117/40
Hence, proved
LHS = RHS
I hope it will help u..
Good morning
Given that the product of two rational number is 117/40
One of those rational number is -13/5
Let the another rational number be x.
Therefore -13/5 × x = 117/40
=> x = 117/40 × -5/13
=> x = 9/-8
=> x = -9/8
VERIFICATION :-
RHS = 117/40
LHS = -9/8 × -13/5
= 117/40
Hence, proved
LHS = RHS
I hope it will help u..
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