Question

the product of two successive integral multiples of 5 is 300 find the multiples​

Answer 1

Answer: Please mark it as brainliest

15 , 20

Step-by-step explanation:

Let 1 St number be 'x'

Let second number be 'x + 5'

So,

x(x+5)=300

x² + 5x = 300

x² + 5x - 300 = 0

Now factorising the above numbers

- b ± ✓b² - 4ac/2a

= - 5 ± ✓(5)² - 4( 1 )( -300 ) / 2( 1)

= - 5 ± ✓ 25 + 1200 / 2

= - 5 ± ✓ 1225 /2

= - 5 ± 35 /2

= - 5 + 35/2. (or). -5 - 35/2

= 30/2 (or). -40/2

x= 15. (or). -20

As negative sign will not come x=15

So, x+5 = 15+5 = 20