Question

the product of two successive multiples of 10 is 1200 .Than find these multiples ....?​

Answer 1

let successive multiples of 10 be 120 and 10 .

so , 120*10 = 1200

Answer 2

Answer:

let the smaller successive number multiple of 10 which product having to 1200 be n

Therefore it success to multiple of 10 which product gives 1200 will n+10

therefor

n(n+10)=1200

n^2+10n=1200

n^2+10n-1200=0

n^2+75n-65n-1200=0

n(n+75)-65(n+75)=0

(n+75)(n-65) =0

n=-75 or n=65