The product of two successive
multiples of five is 300. Determine
the multiples.
Answers
Answered by
1
Hey there!
Let one no. be x so another = x+5
A/Q (x)(x+5) = 300
x2+5x=300
x2+5x-300=0
x2+20x-15x-300=0
x(x+20)-15(x+20)=0
(x+20)(x-15)=0
x=-20 and x=15
the no is positive as specified in the question so x=15
x+5 = 15+5 = 20.
So, the two successive multiples of 5 whose product is 300 are 15 and 20.
Hope it helped!☺️
Let one no. be x so another = x+5
A/Q (x)(x+5) = 300
x2+5x=300
x2+5x-300=0
x2+20x-15x-300=0
x(x+20)-15(x+20)=0
(x+20)(x-15)=0
x=-20 and x=15
the no is positive as specified in the question so x=15
x+5 = 15+5 = 20.
So, the two successive multiples of 5 whose product is 300 are 15 and 20.
Hope it helped!☺️
Answered by
0
multiples are 15 and 20
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