the products of two positive integer is 45 .if one number is greater than the other by 4.find the number
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Let the numbers be a and b
ab = 45 …(1)
a-b = 4, or a = 4+b …(2)
Put (1) in (2)
b(4+b) = 45
b^2+4b=45 = 0
(b+9)(b-5) = 0
Hence b = 5 or -9 and the corresponding value of a = 9 or -5.
The sum of the squares of a and b = 25+81 = 106.
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Answer:
ab=45
because it is product
- a=4+bor a-b=54
- a=9or-5
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