Chemistry, asked by sunitsawant420p9ehd3, 1 year ago

The proper procedure of the experiment to show that zinc is more reactive than copper is... The options are.
a) Prepare a copper sulphate solution and immerse a copper plate in it. b) Prepare zinc sulphate solution and immerse of copper plate in it. c) heat zinc and copper plate. d) add dilute nitric acid to both the plates. Which is the correct one? Give me the answer and I will mark as brainliest


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Answers

Answered by pushpakala086
28

b is the correct answer


Answered by Shardul27
30
B is the correct option
because
the copper being less reactive than zinc doesn't displaces zinc from its salt solution.

Hence,
Zinc is more reactive than Copper.





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sonawaneshobha4: Are bahi galat hai
sonawaneshobha4: CuSo4 +Zn --> ZnSo4+Cu then it it wiil be shown that Zn displaces Cu from its solution then Zn is reactive than Cu
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