Question

The proportion of compounds of nitrogen, phosphorous and potassium in certain fertilizer is 18 : 18 : 10. Here compound of nitrogen is 18%, compound of phosphorous is 18% and that of potassium is 10%. Remaining part is of other substances. Find the weight of each of the above compounds in 20 kg of fertilizer.​

Answer 1

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Let the weight of nitrogen compound in 20 kg of fertilizer be x kg.

∴ $\sf\large\frac{18}{100}$ = $\sf\large\frac{x}{20}$

∴ x = $\sf\large\frac{18 \:x \:20}{100}$ = 3.6

weight of nitrogen compound is 3.6 kg

The percentage of phosphorous compound is also 18%.

$\implies$ Weight of compound of phosphorous is 3.6 kg

If we assume the weight of potassium compound y kg then

$\sf\large\frac{10}{100}$ = $\sf\large\frac{y}{20}$

$\leadsto$ y = 2

$\implies$ weight of potassium compound is 2 kg.

Answer 2

Question

The proportion of compounds of nitrogen, phosphorous and potassium in certain fertilizer is 18 : 18 : 10. Here compound of nitrogen is 18% , Compound of phosphorous is 18% and that of potassium is 10%. Remaining part is of other substances. Find the weight of each of the above compounds in 20 kg of fertilizer.

Given

• The proportion of compounds of nitrogen, phosphorous and potassium in certain fertilizer is 18 : 18 : 10.
• Co.pound if nitrofen is 18%
• Potaasium is 10%

Required to find

Weighr of eaxh of the above compounds in 20kg of fertilizer.

Solution

Let the weight of the nitrogen compound in 20 kg of fertilizer be x kg.

$\sf \implies \dfrac{18}{100} = \dfrac{x}{20}$

$\sf \implies \: x = \dfrac{18 \times 20}{100} = 3.6$

Therefore ,Weight of nitrogen compund is 3.6 kg

The percentage of phosphorous co.pound is also 18%.

Therefore, Weight of compound of phosphorous is 3.6 kg

If we assum the weight of potassium compound y kg then

$\sf \implies \: \dfrac{10}{100} = \dfrac{y}{2}$

therefore, y = 2

Weight of potassium of compound is 2 kg