Question

the prsent average age of a man and his twin sons in 30 years. The ratio of the ages of the man and one of his sons is 5:2. Present age of the man is ?

Answer 1

Let the present age of the man be y years ,
and that of either son be x years ;

Average = (y+x+x)/3
30+3 = 2x+y
90 = 2x+y
y = 90-2x

Ratio
= y:x = 5:2
y/x = 5/2
2y = 5x
y = (5/2)x

90-2x = (5/2)x
(5/2)x + 2 = 90
(9/2) x = 90
x = 10

y = (5/2)x
y = (5/2)×10
y = 25
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Hence the present age of the person is 25 years.

Answer 2

Answer:

Step-by-step explanation:

Sum=90 years

Ratio =5:2:2 (becoz both sons born on the same day)

9x=90

Thn 1x=10

5x=50 (father age)