the pth qth and rth terms of an ap are a,b,c respectively. show that (a-b)r+(b-c)p+(c-a)q=0
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p=a,q=b,r=c
So,
ACC,
(a-b)r+(b-c)p+(c-a)q=0
LHS
=>ac-bc+ab-ac+bc-ab
=>0(. LHS=RHS)
So,
ACC,
(a-b)r+(b-c)p+(c-a)q=0
LHS
=>ac-bc+ab-ac+bc-ab
=>0(. LHS=RHS)
kajalrohani:
thank u
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