Question

The pth term of an a.p is 3p-1/6 then the sum of first n terms will be

Answer 1

Answer:

n/12(3n+1)

Step-by-step explanation:

If pth term is 3p-1/6

Consider nth term simply by change in variable that is 3n-1/6

By putting n=1 u get 1/3 =a

Sn=(n/2) [a(1)+a(n)]

= a(n)=(3-1)/6

= S(n)=(n/2) [(1/2)+(3n-1)/6]

= (n/2) [(3+3n-1)/6]

= (n/2) (3n+2)/6

= 3n^2+2n/12

= n/12(3n+1)

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