The pth term of an AP is (3p - 1)/6. The sum of the first n terms of the AP is
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Answer:
pth term= (3p-1)/6
nth term=(3n-1)/6
ist term=1/3
sum of n terms = n [ 1 + (3n-1) ]
2 3 6
= 3n^2 + n
12
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