Question

The quadratic equation 2x^2+ky+3=0,have equal roots then the value of k is...​

Answer 1

Step-by-step explanation:

Hope this will help you!!!

Answer 2

Answer:

       a) √24

Step-by-step explanation:

2x² + kx + 3 = 0

if it has equal roots, then the determinant = 0

determinant of a quadratic equation = √(b² - 4ac) = 0

a = 2 , b = k , c = 3

√(b² - 4ac) = 0

√(k² - 4 × 2 × 3) = 0

√(k² - 24) = 0   {square both sides}

k² - 24 = 0

k² = 24

k = √24

 ⇒ a) √24