Question

The quadratic equation who roots are 6,i is

Answer 1

Hey there!

The quadratic equation whose roots are a,b is x²-(a+b)x+ab


Given roots=6,i

x²-(6+i)x+6i

=x²-6x-ix+6i

hope it helps

Answer 2

Hello friend,
Roots:- 6 and i
sum of roots=-b/a
(6+i)/1=-b/a
product of roots=c/a
6i/1=c/a
So, a=1
b=-(6+i)
c=6i
Equation:-
ax^2+bx+c
x^2-(6+i)+6i
hope it helps.