Math, asked by rachanars12345, 8 months ago

The quadratic equation whose roots are -2-,3root2​

Answers

Answered by aryan073
1

Step-by-step explanation:

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 {x}^{2}  - ( - 2 + 3 \sqrt{2} )x + ( - 6 \sqrt{2} )

 {x}^{2}   + 2 - 3 \sqrt{2}x  - 6 \sqrt{2}

 {x}^{2}  - 3 \sqrt{2} x + 2 - 6 \sqrt{2}

Answered by Anonymous
0

HERE IS UR ANSWER DEAR,

quadratic equation form..

x²-( sum of the roots )x + (product of roots ) = 0

x²- ( -2 -3√2) x+ 6.√2 = 0

x² + 2 + 3 √2 + 6√2 =0

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