Question

The quadratic equation (x-4) (x-3) has roots

Answer 1

Step-by-step explanation:

Hope this helps you clearly...

Answer 2

Answer:

$(x - 4)(x - 3) = {x}^{2} - 7x + 12 \\ d = {b}^{2} - 4ac = ( { - 7})^{2} - 4 \times 1 \times 12 \\ d = 1 > 0 \\ hence \: roots \: are \: real \: and \: unequal$