Question

the quadratic equation X square + bx + c equal to zero not equal to zero has two distinct real roots

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Answer 1

Answer:

Step-by-step explanation:

$x^{2}+bx+c=0$

$D=b^{2}-4\times 1\times c$

for real and distinct roots

$D\neq 0$

$D>0$

above two condition is satisfied

$x=(-b\pm \sqrt{b^{2}-4\times c})/2$

first root

$x=(-b\-+ \sqrt{b^{2}-4\times c})/2$

second root

$x=(-b\- -\sqrt{b^{2}-4\times c})/2$