The quadratic equation: x2 + 10x + 25 = 0 the roots are P and Q, find P + Q, P-Q, PxQ, P2 + Q2, P3xQ3?
ROYALJATT:
Is it P^2 + Q^2
Answers
Answered by
2
Hey there!
x² + 10x + 25 = 0
(x + 5)² = 0
Twin roots = - 5
P = - 5
Q = - 5
P + Q = - 10
P - Q = 0
P² + Q² = 25 + 25 = 50
P³ x Q³ = - 125 x - 125 = 15625
Hope it helps you!
x² + 10x + 25 = 0
(x + 5)² = 0
Twin roots = - 5
P = - 5
Q = - 5
P + Q = - 10
P - Q = 0
P² + Q² = 25 + 25 = 50
P³ x Q³ = - 125 x - 125 = 15625
Hope it helps you!
Answered by
1
HELLO FRIENDS ,
------------------------------------------------------------------------------------------------------------------
Given equation ,
+ 10x + 25 = 0
⇒ + 5x + 5x + 25 = 0 (spliting middle term)
x (x+ 5) + 5 (x + 5) = 0
(x + 5) * (x + 5) = 0
⇒x = -5 , -5
So both roots are same
I.e P= -5
Q= -5
-----------------------------------
P + Q = - 10
P - Q = 0
P² + Q² = 25 + 25
= 50
P³ x Q³ = - 125 x - 125
= 15625
hope it will help u.
----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
------------------------------------------------------------------------------------------------------------------
Given equation ,
+ 10x + 25 = 0
⇒ + 5x + 5x + 25 = 0 (spliting middle term)
x (x+ 5) + 5 (x + 5) = 0
(x + 5) * (x + 5) = 0
⇒x = -5 , -5
So both roots are same
I.e P= -5
Q= -5
-----------------------------------
P + Q = - 10
P - Q = 0
P² + Q² = 25 + 25
= 50
P³ x Q³ = - 125 x - 125
= 15625
hope it will help u.
----------------------------------------------------------------------------------------------------------------
Best of luck ;)
ROYALJATT
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