Question

The quadratic equation x² = 6x-k has real and equal roots. Find the value of k.​

Answer 1

Answer:

9

Step-by-step explanation:

x²- 6x + k = 0

If the quadratic equation has real and equal roots, then the discriminant= 0

D = 0

b² - 4ac = 0

a = 1

b = -6

c = k

36 - 4(1)(k) = 0

4k = 36

k = 9

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Answer 2

x² = 6x-k

x²-6x+k =0

Comparing the quadratic equation with ax²+bx +c =0

a= 1 , b= -6 and c = k

The quadratic equation has real and equal roots

D=0

D= b²-4ac

(-6)²- 4(1)(k) = 0

36-4k = 0

-4k = -36

k = 9