Question

The quadratic polynomial whose sum and products of zeroes are 4and 8

Answer 1

Answer:

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

Given that,

➢ Sum of the zeroes : α + ß = 4

➢ Product of the zeroes : αß = 8

General form of quadratic equation is

⟹ x² - (α + ß)x + αß = 0

➡ x² - (4) x + 8 = 0

➡ x² - 4x + 8 = 0

Therefore, the quadratic equation is " x² - 4x + 8 "

⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆⬆

Step-by-step explanation:

PLEASE MARK ME AS BRAINLIEST

✌✌✌✌✌

Answer 2

Answer:

x2-4x-8

Step-by-step explanation:

Given ,

sum of the zeroes =4

product of the zeroes =8

to find the polynomial = k( x2- x(alpha + beeta) - (alpha . beeta))

=k(x2-x(4)-8)

If k=1 then 1(x2-4x-8)

therefore x2-4x-8