Question

The quadratic polynomial whose sum of zeros is 3 and product of zeros is -2

Answer 1

$\huge\pink{\underline{\underline{\mathfrak{Solution}}}}$

Given that

★ Sum of zeroes = 3

★ product of zeroes = -2

Then according to questions :-

so, to form a equation,

using formula"

$\boxed{\boxed{\boxed{\boxed{\red{{x}^{2} - (sum\:of \: zeroes)x\: + \: (product\: of \: zeroes)= 0} }}}}$

x² - 3x + (-2) = 0

x² - 3x - 2 = 0

Therefore the required equation is :-

x² - 3x - 2= 0

Answer 2

Answer:

$\alpha + \beta = 3$

$\alpha \beta = - 2$

By the formula

$x {}^{2} +( \alpha + \beta )x + \alpha \beta$

$x {}^{2} - 3x - 2$

___________________________

Peace!