Question

the quadratic polynomial whose zeros are -2 and 2 is .........................​

Answer 1

Answer:

$x^{2} -4$

Step-by-step explanation:

To find the quadratic equation from the zeroes a and b

we need to use them in (x-a)(x-b)

Given zeroes are -2 and 2

So, the quadratic equation is (x-2)(x+2) = $x^{2} -4$

Answer 2

Answer:

The quadratic polynomial whose zeros are -2 and 2 is $x^{2} -4=0$.

Step-by-step explanation:

As per the data given in the question,

zeros of the equation are (-2,2)

We know that general form of quadratic eq. in terms of zeros are,

$x^{2} -(S)x+P=0$

where S= sum of zeros

and P= product of zeros

Now,

$S= -2+2=0\\P=-2\times2=-4$

Putting this in general form, we get

$x^{2} -4=0$

So, the quadratic polynomial whose zeros are -2 and 2 is $x^{2} -4=0$.

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