the quadrilateral PQRS. The sides PQ and Rs are Parallel 'x' is the midpoint of Q R the lines sx and pq extended meet y
(I) are the area of triangle spx and triangle qyx equal? why?
Answers
Answer:
the quadrilateral PQRS. The sides PQ and Rs are Parallel 'x' is the midpoint of Q R the lines sx and pq extended meet y
Step-by-step explanation:
Given :-
The quadrilateral PQRS. The sides PQ and RS are Parallel 'x' is the midpoint of QR, the lines SX and PQ extended meet y .
To find :-
Are the area of ∆SRX and ∆QYX equal? why?
Solution :-
Given that
PQRS is a quadrilateral.
PQ || RS
X is the mid point of QR and SX
The lines SX and PQ extended meet y .
Now,
In ∆ SRX and ∆QYX
SX = XQ ( X is the mid point )
<SXR = QXY (Vertically Opposite angles)
<SRX = <YQX ( PQ || RS , QR is a transversal , alternative interior angles)
By ASA Property
∆ SRX is congruent to ∆ QYX
=> ∆SRX =~ ∆QYX
=> area (∆SRX ) = area (∆QYX)
Since the areas of two congruent triangles are equal.
Answer:-
The area of ∆SRX and the area of ∆QYX are equal.
Used formulae:-
If two parallel lines Intersected by a transversal then,
→ Vertically Opposite angles are equal.
→ Alternative interior angles are equal.
→ Areas of two congruent triangles are equal.