Question

The quantity of a charge that will be transferred by a current flow of 20 A over 1 hour

30 minutes period is​

Answer 1

Solution :

The Quantity of charge transferred is $\sf\:10.8\times\:10^{4}C$

Step by step Explanatíon :

We have ,

Current Flow , I = 20 A

Time , t = 1 hour 30 min

$\sf\implies\:t=90min$

$\sf\implies\:t=90\times60sec$

$\sf\implies\:t=5400sec$

We know that :

Current $\sf\:I=\dfrac{dq}{dt}$

$\sf\implies\:q=Idt$

Thus ,

Charge transferred

$\sf=20\times5400$

$\sf=108\times100$

$\sf=10.8\times10^4\:C$

_________________

More About the topic :

• Charge always flows from a body at higher potential to a body at lower potential
• SI unit of charge coulumb ( C )

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

The quantity of a charge that will be transferred by a current flow of 20 A over 1 hour 30 minutes period is _____.

$\huge{\boxed{\rm{\red{Answer}}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• The quantity of the charge that will be transferred by a current flow of 20 A

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• The quantity of the charge that will be transferred by current flow in 1 hour 30 minutes.

$\large{\boxed{\boxed{\sf{Solution}}}}$

• The quantity of the charge that will be transferred by current flow in 1 hour 30 minutes = 10.8 × 10⁴C

$\large{\boxed{\boxed{\sf{What \: the \: question \: say \: ?}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: concept \: 1{st}}}}}$

• The question says that the quantity of the charge will transfer by the flow of the current of 20 A over in an hour 30 minutes. Then the question ask to find the quantity of charge. We know that A means Ampere.

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

$\large\orange{\texttt{According to the question}}$

$\mapsto$ Given current flow = 20A

$\mapsto$ Given time = 1 hr 30 min

$\large\orange{\texttt{Converting hr into minutes}}$

$\large\purple{\texttt{We know that 1 hr = 60 min}}$

$\large\purple{\texttt{So, 60 + 30}}$

$\large\purple{\texttt{90 minutes}}$

$\mapsto$ Hence, time = 90 min.

$\large\orange{\texttt{Converting min into seconds}}$

$\large\purple{\texttt{We know that 1 min = 60 seconds}}$

$\large\purple{\texttt{So, 90 × 60}}$

$\large\purple{\texttt{5400 seconds}}$

$\mapsto$ Hence, time = 5400 seconds.

$\large\orange{\texttt{We know that}}$

$\large\blue{\texttt{Formula used in this question is given below}}$

$\large\blue{\texttt{Here we have to use the formula of current l}}$

$\bold{\green{\fbox{\green{dq / dt}}}}$

$\large\orange{\texttt{Therefore,}}$

$\bold{\green{\fbox{\green{q = ldt}}}}$

$\large\orange{\texttt{Now,}}$

$\large\underbrace\mathfrak\gray{Charged \ transferred}$

$\leadsto$ 20 × 5400

$\leadsto$ 108 × 100

Scientific Notation ↓

$\leadsto$ 10.8 × 10⁴ C

10.8 × 10⁴C is the answer of this question.

Hope it's helpful

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