the quantity of heat required to raise the temperature of 5kg of water through 20°C is what calorie?
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Explanation:
C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C. Answer is 266.858kj1 calorie = 4.18 Joules
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