The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. Find, if any of these combination(s) has/have the same energy. 1. n = 4, I = 2, ml = 2, ms = -1/2 2. n = 3, 1 = 2, ml = 1, ms = +1/2 3. n = 4, I = 1, ml = 0, ms = +1/2 4. n = 3,1 = 2, ml = -2, ms = -1/2 5.
n = 3,1 = 1, ml = -1, ms = +1/2 6. n = 4,1 = 1, ml = 0, ms = +1/2
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Hence, the six electrons i.e., 1, 2, 3, 4, 5, and 6 are present in the 4d, 3d, 4p, 3d, 3p, and 4p orbitals respectively. Therefore, the increasing order of energies is 5(3p) < 2(3d) = 4(3d) < 3(4p) = 6(4p) < 1 (4d).
Explanation:
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