the ques is 4th one plzzz ans fast......gve the full solution..plzzz
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let the number of sides of the polygon be n.
therefore the sum of the interior angles of a polygon with sides n is (n-2)* 180.
it is given that there are 5 right angles and remaining angles are equal to 195.
therefore sum of interior angles = 5*90+(n-5)*195
hence
(n-2) * 180 = 5 * 90 + ( n-5) * 195
180n - 360= 450 + 195n - 975
15n = 165
n = 165/15 = 11
thus, it has 11 sides.
therefore the sum of the interior angles of a polygon with sides n is (n-2)* 180.
it is given that there are 5 right angles and remaining angles are equal to 195.
therefore sum of interior angles = 5*90+(n-5)*195
hence
(n-2) * 180 = 5 * 90 + ( n-5) * 195
180n - 360= 450 + 195n - 975
15n = 165
n = 165/15 = 11
thus, it has 11 sides.
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