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put -1 and 2 in the 2 polynomials and get the remainders P and Q in terms of a substitute values in 2P+Q=6 get the answer
place x= -1 in 1st polynomial we get 5a-6 which will be the remainder P now put x=2in second we will get 4a-10 which is the second remainder Q now 2p+q=6 so 2(5a-6)+4a-10=6
10a-12+4a-10=6
14a=28 or a=2
place x= -1 in 1st polynomial we get 5a-6 which will be the remainder P now put x=2in second we will get 4a-10 which is the second remainder Q now 2p+q=6 so 2(5a-6)+4a-10=6
10a-12+4a-10=6
14a=28 or a=2
PurvaSharma:
Oh come on! Tell me !
no need to use hit and trial here
this question is structured it has steps how to solve
Alright
why to use hit and trial then
Ok
any doubt you may ask
best of luck for tomorrow
Thanks
I shall ask you .
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