Question

The question is
A man is 20 year old elder to his son. After 10 years, his age becomes twice the age of his son. Find the present age

Answer 1

$\sf{Step-by-step \: explanation}$

Let the child's age be x

Then the man's age will be x+20

10 years later...

Father's age= x+20+10= x+30

Son's age= 2(x+10)

x+30= 2x+20

x-2x= 20-30

-x= -10

As minus will cancel each other then,

x= 10

Present age...

The boys age before 10 years = x, which means 10 years.

The man's age before 10 years= x+20, which means 30 years.

The child's age= $\boxed{10}$

The father's age = $\boxed{30}$
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$\small\sf\green{Thanks!!}$